+-

这是一个错误,我无法弄清楚为什么,任何想法?
LOAD DATA LOCAL INFILE 'H:/Data/DB__Muni/data/msrb_AZ_short1.csv'
INTO TABLE import_mdrp FIELDS TERMINATED BY ';' LINES TERMINATED BY '\r\n'
(
Issuer, cusip6, state, Issue,
page_pointer, @var1, date_rng, cusip9, @var2,
yield, Amt_Offer_Dlr, Amt_Offer_Per, Security_Description,
Fitch, Moody, cusip_img, fitch_img, moody_img
)
SET maturity = STR_TO_DATE(@var2,'%m/%d/%Y')
SET issue_date = STR_TO_DATE(@var1,'%m/%d/%Y')
;
最佳答案
代替
SET maturity = STR_TO_DATE(@var2,'%m/%d/%Y')
SET issue_date = STR_TO_DATE(@var1,'%m/%d/%Y')
尝试
SET maturity = STR_TO_DATE(@var2,'%Y-%m-%d')
SET issue_date = STR_TO_DATE(@var1,'%Y-%m-%d')
更新1
SET maturity = DATE_FORMAT(STR_TO_DATE(@var2, '%m/%d/%Y'), '%Y-%m-%d'),
issue_date = DATE_FORMAT(STR_TO_DATE(@var1, '%m/%d/%Y'), '%Y-%m-%d')
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转载注明原文:mysql – LOAD DATA INFILE使用STR_TO_DATE转换2个日期(@ var1,’%m /%d /%Y’) – 抛出错误 - 乐贴网